Skip to content

shz_cdivf

Markdown
SHZ_INLINE shz_complex_t shz_cdivf(shz_complex_t lhs, shz_complex_t rhs) SHZ_NOEXCEPT;

Divides lhs by rhs, returning the complex result.

NameTypeDescription
lhsshz_complex_t
rhsshz_complex_t

shz_complex_t